4w^2+3w-2=-2w

Solution for 4w^2+3w-2=-2w equation:

4w^2+3w-2=-2w

We move all terms to the left:

4w^2+3w-2-(-2w)=0

We get rid of parentheses

4w^2+3w+2w-2=0

We add all the numbers together, and all the variables

4w^2+5w-2=0

a = 4; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·4·(-2)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{57}}{2*4}=\frac{-5-\sqrt{57}}{8}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{57}}{2*4}=\frac{-5+\sqrt{57}}{8}
$